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Triple Integral

Tool to calculate triple Integral. The calculation of three consecutive integral makes it possible to compute volumes for functions with three variables to integrate over a given interval.

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Triple Integral -

Tag(s) : Functions, Symbolic Computation

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Triple Integral

Triple Integral Calculator


$$ \int\limits_3 \int\limits_2 \int\limits_1 f(var_1,var_2,var_3) $$

First Integral 1








Second Integral 2








Third Integral 3








Tool to calculate triple Integral. The calculation of three consecutive integral makes it possible to compute volumes for functions with three variables to integrate over a given interval.

Answers to Questions

How to calculate a triple integral?

The triple integral calculation is equivalent to a calculation of three consecutive integrals from the innermost to the outermost.

$$ \iiint f(x,y,z) \text{ d}x\text{ d}y\text{ d}z = \int_{(x)} \left( \int_{(y)} \left( \int_{(x)} f(x,y) \text{ d}x \right) \text{ d}y \right) \text{ d}z $$

Example: Calculate the integral of $ f(x,y,z)=xyz $ over $ x \in [0,1] $, $ y \in [0,2] $ and $ z \in [0,3] $ $$ \int_{0}^{3} \int_{0}^{2} \int_{0}^{1} xyz \text{ d}x\text{ d}y\text{ d}z = \int_{0}^{3} \int_{0}^{2} \frac{y^2,z^2}{8} \text{ d}y\text{ d}z = \int_{0}^{3} \frac{z^2}{2} \text{ d}z = \frac{9}{2} $$

Enter the function to be integrated on dCode with the desired upper and lower bounds for each variable and the calculator automatically returns the result.

How to integrate with polar coordinates?

The cylindrical coordinates are often used to perform volume calculations via a triple integration by changing variables:

$$ \iiint f(x,y,z) \text{ d}x\text{ d}y\text{ d}z = \iiint f(r \cos(\theta), r\sin(\theta), z) r \text{ d}r\text{ d}\theta\text{ d}z $$

How to integrate with spherical coordinates?

The spherical coordinates are often used to perform volume calculations via a triple integration by changing variables:

$$ \iiint f(x,y,z) \text{ d}x\text{ d}y\text{ d}z = \iiint f(\rho \cos(\theta) \sin(\varphi), \rho \sin(\theta)\sin(\varphi), \rho \cos(\varphi) ) \rho^2 \sin(\varphi) \text{ d}\rho \text{ d}\theta \text{ d}\varphi $$

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