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Inverse of a Matrix

Tool to invert a matrix. The inverse of a square matrix M is a matrix denoted M^-1 such as que M.M^-1=I where I is the identity matrix.

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Inverse of a Matrix -

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Inverse of a Matrix

Square Matrix Inverse Calculator NxN

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Matrix Modular Inverse Calculator

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See also: Hill Cipher

Answers to Questions (FAQ)

What is the inverse of a matrix? (Definition)

The inverse of a square and invertible matrix $ A $ is a matrix $ A^{-1} $ such that $ A imes A^{-1} = A^{-1} \times A = I $, where $ I $ is the identity matrix.

How to calculate the inverse of an invertible matrix?

The inverse $ M^{-1} $ of a square matrix $ M $ can be calculated using several methods that dCode applies for all square matrix sizes.

— Calculation via transpose of the cofactor matrix:

$$ M^{-1} = \frac{1}{\det M} \left( \operatorname{cof}(M) \right)^\mathsf{T} = \frac{1}{\ det M} \operatorname{comp}(M) $$

This formula requires calculating the determinant of the matrix $ \det M $ as well as the transpose of the cofactor matrix (also called the complementary matrix $ \operatorname{comp}(M) $).

— Calculation using the Gauss pivot method:

The method requires carrying out elementary operations on the rows of the matrix M in order to bring it back to the identity matrix. To obtain the inverse matrix, perform the same operations but this time from the identity matrix.

How to calculate the inverse of a matrix using the minors?

If the matrix is small (2x2 or even 3x3), the cofactor method does not require too many calculations and gives a general formula:

— For a matrix of order 2 (2x2):

$$ M = \begin{bmatrix} a & b \\ c & d \\ \end{bmatrix} \\ \det(M) = ad - bc \\ \operatorname{cof}(M) = \begin{bmatrix} d & -c \\ -b & a \end{bmatrix} \\ \operatorname{comp}(M) = \left( \operatorname{cof}(M) \right)^\mathsf{T} = \begin{bmatrix} d & -b \\ -c & a \end{bmatrix} \\ M^{-1} = \frac{1}{ad - bc} \begin{bmatrix} d & -b \\ -c & a \\ \end{bmatrix} $$

Example: $$ M = \begin{bmatrix} 1 & 2 \\ 3 & 4 \\ \end{bmatrix} \Rightarrow M^{-1} = \frac{1}{\det(M)} \begin{bmatrix} 4 & -2 \\ -3 & 1 \\ \end{bmatrix} = -\frac{1}{2} \begin{bmatrix} 4 & -2 \\ -3 & 1 \\ \end{bmatrix} $$

— For a matrix of order 3 (3x3):

$$ M^{-1} = \begin{bmatrix} a & b & c \\ d & e & f \\ g & h & i \end{bmatrix}^{-1} = \left( \begin{bmatrix} \frac{e i-f h}{-c e g+b f g+c d h-a f h-b d i+a e i} & \frac{c h-b i}{-c e g+b f g+c d h-a f h-b d i+a e i} & \frac{b f-c e}{-c e g+b f g+c d h-a f h-b d i+a e i} \\ \frac{f g-d i}{-c e g+b f g+c d h-a f h-b d i+a e i} & \frac{a i-c g}{-c e g+b f g+c d h-a f h-b d i+a e i} & \frac{c d-a f}{-c e g+b f g+c d h-a f h-b d i+a e i} \\ \frac{d h-e g}{-c e g+b f g+c d h-a f h-b d i+a e i} & \frac{b g-a h}{-c e g+b f g+c d h-a f h-b d i+a e i} & \frac{a e-b d}{-c e g+b f g+c d h-a f h-b d i+a e i} \end{bmatrix} \right) $$

How to calculate the inverse of a matrix using Gauss's pivot?

Form an augmented matrix by concatenating the matrix A with the corresponding identity matrix, i.e. a matrix of the form [A | I].

Apply the Gaussian pivot method to reduce the left part (matrix A) to a reduced echelon form, by performing elementary row operations.

If the reduced form is the identity matrix, then the right part is the inverse of the A matrix.

This method may take longer in calculation time but can be used to check the inverse of a matrix.

How to prove that a matrix is invertible?

A matrix is invertible if its determinant is non-zero (different from 0). So to prove that a matrix has an inverse, calculate the determinant of the matrix, if it is different from 0, then the matrix is invertible.

A non invertible matrix is called singular (inversion is not possible).

Avoid the term inversible which is wrong.

How to inverse a matrix with zero determinant?

A matrix with a determinant equal to 0 is not invertible. It does not have an inverse, it is not possible to calculate its inverse.

How to check that a matrix is the inverse of another?

The multiplication of the matrix by its inverse must give the identity matrix. So the computation of $ M . M^{-1} = I $.

How to calculate the modular inverse of a matrix?

The principle is the same, but instead of calculating the determinant, calculate the modular inverse of the matrix determinant. See Hill cipher.

How to solve a system of linear equations with an inverse matrix?

Solving a system of linear equations $ A \times X = B $ where $ A $ is an invertible matrix, involves calculating the inverse of $ A $, the matrix $ A^{-1} $ obtained can then be multiplied on both sides of the equation to obtain $ X = A^{-1} \times B $.

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