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Newton Interpolating Polynomial

Tool to find the equation of a curve via Newton's algorithm. Newtonian Interpolating algorithm is a polynomial interpolation/approximation allowing to obtain the Lagrange polynomial as equation of the curve by knowing its points.

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Newton Interpolating Polynomial -

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Newton Interpolating Polynomial

Newtonian Interpolation Calculator


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Answers to Questions (FAQ)

What is Newton's interpolation? (Definition)

Newton interpolation refers to a method for constructing an interpolation polynomial passing through a set of points $(x_i,y_i)$. It is based on the calculus of divided differences and provides a polynomial in a factored form that allows for the easy addition of new points without recalculating everything.

How to find the equation of a curve using Newton algorithm?

To find the Newton interpolation polynomial associated with points $ (x_i,y_i) $, use divided differences to construct the Newton form of the polynomial. From $ n+1 $ known points, the polynomial can be written

$$ P(x)= [y_0] + [y_0,y_1] (x-x_0) + \ldots + [y_0,\ldots ,y_n] (x-x_0) \ldots (x-x_{n-1}) $$

with the notation $ [y_i] $ for divided differences.

Each coefficient $ [y_0,\ldots,y_k] $ is calculated using the values $ (x_i,y_i) $.

Example: Curve whose points (1,3) and (2,5) are known. $$ P(x) = [y_0] + [y_0,y_1] (x-x_0) \\ = 3 + \left(\frac{3}{1-2}+\frac{5}{2-1}\right) (x-1) = 3+2(x-1) = 2x+1 $$

What are Newton Divided Differences?

Newton Divided Differences are noted $ [y_i] $ and computed by the formula $$ [y_0,\dots ,y_k]=\sum_{j=0}^k {\frac{y_j}{\prod_{0\leq i\leq k,\,i\neq j}(x_j-x_i)}} $$ they intervene in the computation of Newton's interpolation.

Example: For two points: $ [y_i,y_{i+1}] = \frac{y_{i+1} - y_i}{x_{i+1} - x_i} $

NB: If $ k = 0 $, then the product $ \prod(x_j-x_i) = 1 $ (empty product)

What is the link between Newton's and Lagrange's interpolations?

Both forms describe the same interpolation polynomial. The Lagrange form uses basic polynomials $ L_i(x) $, while the Newton form relies on factored products $ (x-x_0)\ldots(x-x_{k-1}) $. The two constructions are algebraically equivalent, but the Newton form is more convenient for adding a point without a complete recalculation.

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