Tool to decompose in prime factors. In Mathematics, the prime factors decomposition (also known as Prime Integer Factorization) consists in writing a positive integer with a product of prime factors

Prime Factors Decomposition - dCode

Tag(s) : Arithmetics

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Tool to decompose in prime factors. In Mathematics, the prime factors decomposition (also known as Prime Integer Factorization) consists in writing a positive integer with a product of prime factors

The decomposition into prime factors of a number \( N \) requires attempting to divide the number \( N \) by the set of prime factors \( p \) which are less than \( N \). If \( p \) is a divisor of \( N \) then start again by taking \( N = N/p \) as long as there are any possible divisors.

Example: If \( N = 147 \), the prime numbers less than \( N = 147 \) are \( 2, 3, 5, 7, 11, 13, ... \). To find the decomposition into a product of prime factors of \( 147 \), begin by attempting the division by \( 2 \), \( 147 \) is not divisible by \( 2 \). Then divide by \( 3 \), \( 147/3 = 49 \) so \( 147 \) is divisible by \( 3 \) and \( 3 \) is a prime factor of \( 147 \). Then, no longer take \( 147 \) but \( 147/3 = 49 \). The prime numbers less than \( 49 \) are \( 2, 3, 5, 7, 11, 13, ... \), try to divide \( 49 \) by \( 2 \) and so on.

Example: Finally, it remains the factors \( 3, 7, 7 \) and check that \( 3 * 7 * 7 = 147 \), or write \( 147 = 3 * 7 ^ 2 \).

This decomposition is possible whatever the starting number, it is a fundamental theorem of arithmetic.

Example: \( 123 = 3 * 41 \), \( 1234 = 2 * 617 \), \( 12345 = 3 * 5 * 823 \) or \( 123456 = 2 ^ 6 * 3 * 643 \

The problem with this method (or algorithm) is that it is very long when the numbers are very large. As soon as the factors have more than 15-20 digits and are not trivial, it takes several days of calculations, even for the most powerful computers.

dCode allows numbers up to 250 digits, but will stop calculation if it requires too many resources or takes too long.

It exists several algorithms : classical iterative division, Pollard rho algorithm, elliptic curves, and the quadratic sieve algorithm. dCode uses a combination of all them to be very fast.

The whole list of prime numbers starts with : 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199 211 223 227 229 233 239 241 251 257 263 269 271 277 281 283 293 307 311 313 317 331 337 347 349 353 359 367 373 379 383 389 397 401 409 419 421 431 433 439 443 449 457 461 463 467 479 487 491 499 503 509 521 523 541 547 557 563 569 571 577 587 593 599 601 607 613 617 619 631 641 643 647 653 659 661 673 677 683 691 701 709 719 727 733 739 743 751 757 761 769 773 787 797 809 811 821 823 827 829 839 853 857 859 863 877 881 883 887 907 911 919 929 937 941 947 953 967 971 977 983 991 997... and there are an infinite number of primes.

The demonstration of the infinity of prime numbers is :

If \( P \) is a prime number and \( P\# \) the Primorial of \( P \) : the product of \( 2*3*5*......*P \) of all the prime numbers between \( 2 \) and \( P \). If \( Q = P\#+1 \), then, the rest of the euclidean division of \( Q \) by any prime number inferior to \( P \) will be \( 1 \). So, all prime factors of \( Q \) (\( Q \) can be prime) are prime numbers superior to \( P \). It will always exists prime numbers superiors to \( P \).

`// javascript`

function prime_factors(n) {

if (!n || n < 2)

return [];

var f = [];

for (var i = 2; i <= n; i++){

while (n % i === 0){

f.push(i);

n /= i;

}

}

return f;

};

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Source : https://www.dcode.fr/prime-factors-decomposition

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