Discriminant of a Polynomial

Question 1

Answer

For a quadratic polynomial $ ax^2+bx+c $, the discriminant named delta $ \Delta $ is calculated with the formula:

$$ \Delta = b^2-4ac $$

The fact of knowing the value of the discriminant then solves the equation more easily through formulas (using this discriminant).

Example: The equation $ 2x^2+3x+1 = 0 $ of type $ ax^2+bx+c $ (with $ a = 2 $, $ b = 3 $ et $ c = 1 $) has $ \Delta = b^2-4ac = 3^2-4*2*1 = 1 $

For a cubic polynomialof the form $ax^3+bx^2+cx+d$ the discriminant is $$ \Delta = b^2c^2-4ac^3-4b^3d-27a^2d^2+18abcd $$

For a polynomial of degree 1 or 0 the determinant is not generally calculated, its value has no interest.

Question 2

Answer

For a quadratic polynomial of type $ ax^2+bx+c = 0 $

If the discriminant is positive (strictly), the equation has two solutions:

$$ x_1 = \frac {-b + \sqrt \Delta}{2a} $$

$$ x_2 = \frac {-b - \sqrt \Delta}{2a} $$

Example: The equation $ 2x^2+3x+1 = 0 $ has $ \Delta = 1 $ so solutions are $ x_1 = -1/2 $ and $ x_2 = -1 $

If the discriminant is zero, the equation has a double root:

$$ x_1=x_2 = -\frac b{2a} $$

If the discriminant is negative (strictly), the equation has complex solutions:

$$ \delta^2 = \Delta $$

$$ x_1 = \frac {-b + \delta}{2a} $$

$$ x_2 = \frac {-b - \delta}{2a} $$

For equations of higher degrees, the calculations are much more complicated, but knowledge of the determinants is important.

Discriminant Calculator