Tool to calculate the Levenshtein distance between 2 words (character string) and search for related words in the dictionary or in a list.

Levenshtein Distance - dCode

Tag(s) : Data Processing

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The **Levenshtein distance** is an algorithmic method allowing to quantify a distance between two words (more generally between 2 strings of characters). Two close words (that is to say that few things separate them spelling: they have several letters in common, in the same position) will then have a small distance, while two very different words will have a large distance. This distance is also called edit distance and is equal to the minimum number of characters to be deleted, inserted, or replaced to move from one string to another.

__Example:__ TAKE and MAKE are similar graphically (a kind of near-homograph) and have a **Levenshtein distance** of 1

__Example:__ CLOSE and CLOTHES are similar phonetically (homophone) but orthographically far apart, they have a **Levenshtein distance** of 3

The distance from **Levenshtein** is symmetrical, the distance value from STRING1 to STRING2 is equal to the distance value from STRING2 to STRING1

**Levenshtein**'s algorithm evaluates the number of differences between the two character strings, the differences can be of 3 types: a substitution (replacement of one character by another), an insertion (addition of a new character) or a deletion (deletion of a character).

$$ \operatorname{Distance}(a,b) = \begin{cases} ||a|| & \text{ if } ||b|| = 0, \\ ||b|| & \text{ if } ||a|| = 0, \\ \operatorname{Distance}(a', b') & \text{ if } a[0] = b[0] \\ 1 + \min \begin{cases} \operatorname{Distance}(a', b) \\ \operatorname{Distance}(a, b') \\ \operatorname{Distance}(a', b') \\ \end{cases} & \text{ otherwise } \end{cases} $$

With $ ||a|| $ the size of the string, and $ a' $ the string $ a $ deprived of its first character (noted $ a[0] $)

The **Levenshtein distance** measures the similarity between two strings of characters.

__Example:__ DCODE is at a distance of 2 from DECODER (1- add E and 2- add R)

__Example:__ DECODER is at a distance of 2 from DCODE (1- remove E and 2- remove R)

Use the dCode tool by entering a word and a dictionary with which to compare the word.

All words with a similar spelling will be returned.

Calculating the distance between 2 strings of characters can make it possible to know their quantity of differences and thus also their amount of similarity. So the **Levenshtein** calculation algorithm can be used to determine typing errors or misspellings, words for which the proximity of the compared chains is strong.

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Source : https://www.dcode.fr/levenshtein-distance

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